Part 1 contains 19 short answer questions, including 15 questions basic level complexity (the serial numbers of these tasks: 1, 2, 3, 4, ...15) and 4 tasks of an increased level of complexity (the serial numbers of these tasks: 16, 17, 18, 19). Despite all their differences, the tasks in this part are similar in that the answer to each of them is written briefly in the form of one number or a sequence of numbers (two or three). The sequence of numbers is written on the answer form without spaces or other additional characters.
Part 2, depending on the CMM model, contains 3 or 4 tasks high level complexity, with a detailed answer. The difference between exam models 1 and 2 lies in the content and approaches to completing the last tasks of the exam options:
Examination model 1 contains task 22, which involves performing a “thought experiment”;
Examination model 2 contains tasks 22 and 23, which involve completing laboratory work(real chemical experiment).
"2"– from 0 to 8
"3"– from 9 to 17
"4"– from 18 to 26
"5"– from 27 to 34
Correct completion of each of tasks 1–15 is scored 1 point. Correct completion of each of tasks 16–19 is assessed with a maximum of 2 points. Tasks 16 and 17 are considered completed correctly if two answer options are correctly selected in each of them. For an incomplete answer - one of two answers is correctly named or three answers are named, two of which are correct - 1 point is given. The remaining answer options are considered incorrect and are scored 0 points. Tasks 18 and 19 are considered completed correctly if three correspondences are correctly established. An answer in which two out of three matches are established is considered partially correct; it is worth 1 point. The remaining options are considered an incorrect answer and are scored 0 points.
The tasks of Part 2 (20–23) are checked by a subject commission. Maximum score for a correctly completed task: for tasks 20 and 21 - 3 points each; in model 1 for task 22 – 5 points; in model 2 for task 22 - 4 points, for task 23 - 5 points.
To complete the examination work in accordance with model 1, 120 minutes are allotted; according to model 2 – 140 minutes
The OGE in chemistry is taken only at the student’s choice; this test is not included in the list of mandatory ones. Chemistry is chosen by students who, after 9th grade, plan to enter a specialized 10th grade school or a specialized college or technical school. To enter medical school, you need to take not only chemistry, but also biology. The exam implies orientation in theory and successful application of it in practice. The test subject needs to solve many tasks of different difficulty levels from wide range topics To decide which topics to pay attention to, read the OGE preparation program in chemistry.
The exam consists of tasks, which are divided into two logical blocks:
At the end of 9th grade, schoolchildren are required to pass the final state certification. The test consists of passing several mandatory exams.
State Examination in Chemistry 2018 is not mandatory. Chemistry is a discipline that students have the right to independently choose for examination.
It is worth noting that state certification is necessary to obtain a certificate of incomplete school education. Also, the GIA is an intermediate stage of preparation for final exams in 11th grade. However, the exam results are not reflected in the certificate in any way.
Every year, certain adjustments are made to the state certification process and form. This is necessary to ensure that students are able to fully demonstrate their abilities in the examination.
The updated OGE procedure will include three possibilities correct negative exam results and extend the period for retakes.
Changes are also possible regarding the calculation of results, namely, it is planned to develop a unified federal point scale, according to which the exam results will be calculated. It is worth noting that the data will not be tied to regional indicators.
Concerning chemistry exams, then no significant changes are expected here.
Total number of tasks in KIMah in chemistry is 22 . All questions are divided into two parts. The first category is represented by questions as answers to which you need to indicate the correct answer. In this part of everything 19 tasks and for the correct answer the examinee receives 1 point.
The second block consists of questions of increased complexity, for which you need to write a detailed answer or solution. There are only four questions in this part and for each correct answer the student receives 3 to 5 points.
By corresponding order Ministry of Education of the Russian Federation There are certain categories of students who have the right to register an application for state certification.
Schoolchildren who have completed 9 grades and have grades in all subjects of at least C can try their hand at the final certification. Those students who have an “unsatisfactory” grade in one discipline are also allowed to take the state exam, but this discipline is included in the list of exams that the teenager will take.
Also, those students who in previous periods passed the exam unsatisfactorily or with results that did not suit them for a number of reasons have the right to take the exam.
Final certification in chemistry in early period will take place in 2018 April 27, in the main period – June 7. For those who wanted to improve their results, a retake was carried out - 12-th of September.
The student is required not only to prepare for the exam, but also to register his written desire to become a participant in the State Examination.
To do this, the student must submit an application in a unified form to school administration at the place of training. Such an application must be submitted before 1st of February.
In order for the document to be registered, and in the future, the student will have the opportunity to take exams, the application must be submitted in person, and provide a passport or other identification document. In addition, the application must indicate all the disciplines in which the student plans to take an exam.
It is possible to change the list of subjects in the future, however, to do this, the student will need to submit an explanatory document with copies of supporting documents attached to it. Changes can be made no later than a month before state certification.
Until recently, only those students who were unable to attend the state certification on time could take the early examination. These schoolchildren included those children who were involved in sports, undergoing treatment or going to study abroad.
This option has both advantages and disadvantages. The advantage of early state certification is that schoolchildren have more time to prepare if they fail the exam. Also, children do not have to worry about missing exam deadlines.
However, the disadvantages are also significant. Schoolchildren are subject to additional psychological and physiological stress. Students have to combine basic studies with preparation for exams, which, of course, is the reason for the violation of the regime and as a result of unimportant results at the State Examination Test.
Quite often students use it to prepare for exams. demo version of FIPI GIA in chemistry 2018. Demo option– these are materials that include groups of tasks presented at state certifications of previous years. Materials are stored in Open task bank on the official website of FIPI(fipi.ru).
The form of the materials is in full compliance with the CMMs that will be offered for state certification, with the exception of numerical indicators.
The manual is quite suitable for a student to practice completing assignments and identify topics that require additional preparation. Also, a ninth grader will be able to draw up a plan for completing tasks for state certification.
Our website offers the most modern demo versions of GIA tasks in chemistry and, if desired, you can download and print them.
The list of items permitted for State Examination is approved annually. You are allowed to take a black, gel or capillary pen and a passport with you to the chemistry exam. Also, for state certification in this discipline, you can use D.I. Mendeleev’s periodic system of chemical elements, a table of solubility of salts, acids and bases in water, an electrochemical series of metal voltages and a non-programmable calculator.
Cannot be brought for state certification mobile phone and other electronic computing devices. It is also not permitted to use other reference materials not permitted by the organizers.
In order for the exam to be accepted, the student must score at least 9 points. This result corresponds to the mark “satisfactory”. The “Excellent” rating corresponds to the result in 34 points.
From time to time, situations arise during examinations when schoolchildren do not agree with the result of state certification or believe that the examination procedure was violated by the organizers. In this case, examinees have the right to protest those points with which they do not agree.
If a student believes that the examination process did not comply with mandatory standards, then he, without leaving the classroom, must contact the conflict commission in writing and demand a retake. If the student’s grade does not triple, then he has the right to demand a re-check of his work. It is noteworthy that all work will be checked in its entirety and the verification must be carried out by other experts. To do this, the student must write an application to the conflict commission within four days deadline and justify your claims.
It may be refused if the complaint expresses claims regarding the content or form of the assignments. Also, the conflict commission can refuse a student if the student himself caused a violation of the state certification procedure.
Preparation for the State Examination in Chemistry 2018 It takes a lot of time, but it is very important to use the right aids correctly. Only the choice of the most the best way training can ensure good performance during state certification. Most best option preparation includes the comprehensive use of the demo version of the State Academic Examination in Chemistry, online tests in chemistry, demonstration materials and various books and collections of problems.
The following brochures and textbooks can be used as aids:
All materials help the student briefly repeat previously studied theory and practice in practice.
The GIA demo version and demonstration materials provide an opportunity to get acquainted with the structure of exam tasks, as well as identify those topics that need repetition. Online testing is used when training is required regarding the time spent on exam tasks.
In order to pass the test successfully, the student needs to take care of his attitude. Positive mood during preparation and at the state certification itself guarantees good results according to the exam.
It is extremely important for parents to help their child. In order for a student to fully prepare for state certification, an atmosphere of peace and understanding is necessary.
Over the past few years, an exam such as the State Examination in Chemistry has not been popular among schoolchildren. Only a small percentage of students chose this subject. Statistics from previous years show that due to the fact that there was little time to complete tasks and the tasks were difficult, children did poorly in the chemistry exam. 100 points were absent, and the number of “B students” was large. Over time, the situation began to change and today, 100-point students have already appeared, and the percentage of “B” students has decreased by 0,6% .
Training test for preparation for the OGE - 2018 in chemistry in 9th grade
Instructions for performing the work
2 hours (120 minutes) are allotted to complete the work. The work consists of 2 parts, including 22 tasks. Part 1 contains 19 short-answer tasks, part 2 contains 3 long-answer tasks.
Answers to tasks 1-15 are written in the form of one number, which corresponds to the number of the correct answer.
Answers to tasks 16-19 are written as a sequence of numbers.
For tasks 20-22, you should give a complete, detailed answer, including the necessary reaction equations and the solution to the problem.
When doing work you can use Periodic table chemical elements D.I. Mendeleev, a table of solubility of salts, acids and bases in water, an electrochemical series of metal voltages and a non-programmable calculator.
Part 1
1.Chemical element The 2nd period of the VIA group corresponds to the electron distribution scheme
1) Fig. 1
2) Fig. 2
3) Fig. 3
4) Fig. 4
Answer:
2. Non-metallic properties simple substances intensify in series
1) phosphorus → silicon → aluminum
2) fluorine → chlorine → bromine
3) selenium → sulfur → oxygen
4) nitrogen → phosphorus → arsenic
Answer:
3. A covalent polar bond is realized in a substance
1) CuO
2) P 4
3)SO2
4) MgCl 2
Answer:
4 . In which compound does the oxidation state of chlorine equal to +7?
1)HCl
2) Cl 2 O
3) KClO 3
4) KClO 4
Answer:
5. Substances whose formulas are ZnO and Na 2 SO 4 , are respectively
1) basic oxide and acid
2) amphoteric hydroxide and salt
3) amphoteric oxide and salt
4) main oxide and base
Answer:
6. A reaction whose equation is
2NaOH + CuCl 2 = Cu(OH) 2 + 2NaCl
refers to reactions
1) decomposition
2) connections
3) substitution
4) exchange
Answer:
7. The smallest amount of positive ions is formed during the dissociation of 1 mol
1) nitric acid
2) sodium carbonate
3) aluminum sulfate
4) potassium phosphate
Answer:
8. The irreversible occurrence of the ion exchange reaction between solutions of barium hydroxide and potassium carbonate is due to the interaction of ions
1) K + and OH -
2) K + and CO 3 2―
3) Ba 2+ and CO 3 2―
4) Ba 2+ and OH -
Answer:
9. Copper reacts with solution
1) AgNO3
2) Al 2 (SO 4 ) 3
3) Fe SO 4
4) NaOH
Answer:
10 . Copper(II) oxide can react with each substance in the pair
1) HCl, O 2
2) Ag, SO 3
3) H 2, SO 4
4) Al, N 2
Answer:
11 . Determine the formula of the unknown substance in the reaction scheme:
KOH + …→ K 2 CO 3 +H2O
1) CO
2) CO2
3) CH 4
4) C
Answer:
12. You can convert CaNO3 to CaSO3 using
1) hydrogen sulfide
2) barium sulfite
3) sodium sulfite
4) sulfur dioxide
Answer:
13. Are the judgments about the methods of separating mixtures correct?
A. Evaporation is referred to as physical means separation of mixtures.
B. Separation of a mixture of water and ethanol is possible by filtration.
1) only A is correct
2) only B is correct
3) both judgments are correct
4) both judgments are incorrect
Answer:
14. In the reaction 3CuO + 2NH 3 = 3Cu+ N 2 + 3H 2 O
The change in the oxidation state of the oxidizing agent corresponds to the diagram
1) +2 → 0
2) −3 → 0
3) −2 → 0
4) 0 → +2
Answer:
15 . On which diagram is the distribution of mass fractions of elements
corresponds to NHNO 3
Part 2
16. When completing a task, choose two correct ones from the proposed list of answers and write down the numbers under which they are indicated.
In the series of chemical elements Be- Mg- Ca
1) atomic radius increases
2) the highest oxidation state increases
3) the value of electronegativity increases
4) the basic properties of the formed hydroxides increase
5) the number of electrons in the external level decreases
Answer:
18. Establish a correspondence between two substances and a reagent that can be used to distinguish between these substances.
SUBSTANCES | REAGENT |
|
A) NaNO 3 and Ca(NO 3) 2 B) FeCl 2 and FeCl 3 B) H 2 SO 4 and HNO 3 | 1) BaCl2 2) Na 2 CO 3 3) HCl 4) NaOH |
Write down the numbers in your answer, arranging them in the order corresponding to the letters:
19. Match the substance with the reagents with which it can react.
Answer:
20. Using the electronic balance method, arrange the coefficients in the reaction equation, the diagram of which
P + H 2 SO 4 →H 3 PO 4 + SO 2 + H 2 0
Identify the oxidizing and reducing agent
2, H 2 SO 4, CaCO 3
Assessment system for test work in chemistry
Correct completion of each task part 1 Basic difficulty level (1–15) is scored 1 point.
Correct completion of each task part 1 increased level of complexity (16–19) is assessed with a maximum of 2 points. Tasks 16 and 17 are considered correctly completed if two answer options are correctly selected in each of them. For an incomplete answer - one of two answers is correctly named or three answers are named, two of which are correct - 1 point is given. The remaining answer options are considered incorrect and are scored 0 points.
Tasks 18 and 19 are considered completed correctly if three correspondences are correctly established. An answer in which two out of three matches are established is considered partially correct; it is worth 1 point. The remaining options are considered an incorrect answer and are scored 0 points.
Part 1
Part 2
20. Using the electronic balance method, arrange the coefficients in the reaction equation, the diagram of which is:
HNO 3 + Zn = Zn(NO 3 ) 2 + NO + H 2 O
Specify the oxidizing agent and the reducing agent.
Response Elements |
|
1) Let's create an electronic balance: S +6 + 2ē = S +4 │2 │5 P 0 - 5ē = P +5 │5 │2 2) We point out that S +6 (H 2 SO 4 ) is an oxidizing agent, and P 0 (P)-reducing agent 3) Let’s arrange the coefficients in the reaction equations: 2P + 5H 2 SO 4 →2H 3 PO 4 + 5SO 2 + 2H 2 0 |
|
Evaluation criteria | Points |
There was an error in only one of the elements in the answer. | |
There were errors in two elements in the answer | |
Maximum score | |
21. When an excess solution of potassium carbonate reacted with a 10% solution of barium nitrate, 3.94 g of sediment precipitated. Determine the mass of the barium nitrate solution taken for the experiment.
Response Elements (other wording of the answer is allowed that does not distort its meaning) |
|
Explanation.
K 2 CO 3 + Ba(NO 3 ) 2 = ↓ + 2KNO 3 2) The amount of barium carbonate substance and the mass of barium nitrate are calculated: N(BaCO 3 ) = m(BaCO 3 ) / M(BaCO 3 ) = 3.94: 197 = 0.02 mol n (Ba(NO 3 ) 2 ) = n(BaCO 3 ) = 0.02 mol m (Ba(NO 3 ) 2 ) = n (Ba(NO 3 ) 2 ) M (Ba(NO 3 ) 2 ) = 0.02 261 = 5.22 g. 3) The mass of the barium nitrate solution was determined: M (solution) = m(Ba(NO 3) 2 / ω (Ba(NO 3) 2 = 5.22 / 0.1 = 52.2 g Answer: 52.2 g. |
|
Evaluation criteria | Points |
The answer is correct and complete, includes all the named elements | |
2 elements from the above are written correctly | |
Correctly written 1 element from the above (1st or 2nd) | |
All elements of the answer are written incorrectly | |
Maximum score | |
22. Given substances: CuO, NaCl, KOH, MnO 2, H 2 SO 4, CaCO 3
Using water and the necessary substances only from this list, obtain copper(II) chloride in two stages. Describe the signs of the reactions being carried out. For the second reaction, write the abbreviation ionic equation reactions.
Response Elements (other wording of the answer is allowed that does not distort its meaning) |
|
Let's write 2 reaction equations: 2NaCl + H 2 SO 4 = 2HCl+ Na 2 SO 4 CuO +2HCl =CuCl 2 +H 2 O Let us indicate the signs of reactions. For the first reaction - gas evolution. For the dissolution reaction of CuO - a color change, the formation of a blue solution. Let's create a shortened ionic equation for the first reaction: CuO +2H + =Cu 2+ +H 2 O |
|
Evaluation criteria | Points |
The answer is correct and complete, includes all the named elements | |
Four elements of the answer are written correctly | |
Three elements of the answer are written correctly | |
Two elements of the answer are written correctly | |
One element of the answer is correctly written | |
All elements of the answer are written incorrectly | |
Maximum score | |
2018
The maximum number of points that an examinee can receive for completing the entire examination paper (without the actual experiment) is 34 points.
Table 4
Scale for converting the primary score for completing an examination paper into a mark on a five-point scale (work without a real experiment, demo version 1)
It is recommended to mark “5” if, out of the total amount of points sufficient to obtain this mark, the graduate scored 5 or more points for completing tasks in Part 3. The exam results can be used when admitting students to specialized classes high school. The guideline for selection into specialized classes can be an indicator whose lower limit corresponds to 23 points.
Option
control measuring materials for
holding in 2017 the main state
CHEMISTRY exam
Instructions for performing the work
The examination paper consists of two parts, including 22 tasks. Part 1 contains 19 short-answer tasks, part 2 contains 3 long-answer tasks.
You are given 2 hours (120 minutes) to complete the exam paper in chemistry.
Answers to tasks 1–15 are written as one number, which corresponds to the number of the correct answer. Write this figure in the answer field in the text of the work, and then transfer it to answer form No. 1.
Answers to tasks 16–19 are written as a sequence of numbers. Write this sequence of numbers in the answer field in the text of the work, and then transfer it to answer form No. 1.
For tasks 20–22, you should give a complete, detailed answer, including the necessary reaction equations and calculations. The tasks are completed on answer form No. 2.
When performing work, you can use the Periodic Table of Chemical Elements D.I. Mendeleev, a table of solubility of salts, acids and bases in water, an electrochemical series of metal voltages and a non-programmable calculator.
When completing assignments, you can use a draft. Entries in the draft are not taken into account when grading work.
The points you receive for completed tasks are summed up.
Try to complete as many tasks as possible and score the most points.
We wish you success!
Part 1
The answer to tasks 1–15 is one number, which corresponds to the number of the correct answer. Write this number in the answer field in the text of the work, and then transfer it to ANSWER FORM No. 1 to the right of the number of the corresponding task, starting from the first cell.
A chemical element of the 3rd period of the VA group corresponds to a diagram of the distribution of electrons across layers:
An ionic bond is characteristic of each of two substances:
1) potassium chloride and hydrogen chloride
2) barium chloride and sodium oxide
3) sodium chloride and carbon monoxide (IV)
4) lithium oxide and chlorine
Answer:Each of the two substances is complex
1) water and chlorine
2) water and hydrogen
3) hydrogen and quartz
4) benzene and water
Answer:The largest number of positive ions is formed during the dissociation of 1 mol
1) sulfuric acid
2) sodium phosphate
3) iron(III) nitrate
4) potassium sulfide
Answer:Both substances of the pair react with water at room temperature
1) oxygen and carbon
2) magnesium and sulfur
3) aluminum and phosphorus
4) sodium and calcium
Answer:Among the substances: Zn, Al 2 O 3, Cu(OH) 2, BaCl 2 - reacts with a solution of sulfuric acid (s)
4) four
Answer:Are the judgments about the methods of separating mixtures correct?
A. Evaporation is a physical method for separating mixtures.
B. Separation of a mixture of water and ethanol is possible by filtration.
1) only A is correct
2) only B is correct
3) both judgments are correct
4) both judgments are incorrect
| The element carbon is an oxidizing agent in the reaction |
||||||||||||
|
The answer to tasks 16–19 is a sequence of numbers that should be written in ANSWER FORM No. 1 to the right of the number of the corresponding task, starting from the first cell. Write your answer without spaces, commas or other additional characters.
Write each number in a separate box in accordance with the samples given in the form.
When completing tasks 16, 17, from the proposed list of answers, select two correct ones and write down the numbers under which they are indicated in the table.
16. What magnesium and silicon have in common is
1) the presence of three electronic layers in their atoms
2) the existence of simple substances corresponding to them in the form of diatomic molecules
3) the fact that they belong to metals
4) the fact that their electronegativity value is less than that of phosphorus
5) their formation of higher oxides with the general formula EO 2
Answer:When completing tasks 18, 19, for each element of the first column, select the corresponding element from the second column. Write down the selected numbers in the table under the corresponding letters. The numbers in the answer may be repeated.
|
| Match the name of the substance with the reagents with which this substance can interact. |
Do not forget to transfer all answers to answer form No. 1 in accordance with the instructions for completing the work.
Part 2
For answers to tasks 20–22, use ANSWER FORM No. 2.
First write down the number of the task (20, 21 or 22), and then the detailed answer to it. Write down your answers clearly and legibly.
20. Using the electron balance method, create an equation for the reaction
KMnO 4 + KOH → K 2 MnO 4 + O 2 + H 2 O
Identify the oxidizing agent and the reducing agent.
21. An excess of potassium hydroxide solution was added to 376 g of a solution with a mass fraction of copper (II) nitrate of 7.5%. Determine the mass of the deposited sediment.
22. Given substances: Zn, HCl (solution), H 3 PO 4, AgNO 3, NH 4 Cl, Ba(NO 3) 2. Using water and the necessary substances only from this list, obtain zinc nitrate in two stages. Describe the signs of the reactions being carried out. For an ion exchange reaction, write the abbreviated ionic equation for the reaction.
